fd equivalent for finding multiple owners?

[pbe9394]

Hello,

Is there a fd equivalent for something like find ./ -user user1 -o -user user2 -o -user user3 ...

Thanks!

[ShreeChaturvedi]

fd's --owner only takes one user, and repeating the flag just keeps the last one. The simplest workaround is combining calls:

{ fd --owner user1; fd --owner user2; fd --owner user3; } | sort -u

sort -u deduplicates, though with distinct users you won't get overlap.

If you want a single pass instead, you can filter with --exec:

fd --exec sh -c 'case "$(stat -c %U "$1")" in user1|user2|user3) echo "$1";; esac' _ {}

That's slower because it shells out to stat on every match, so the multi-call version is usually better for large trees.