npm install pca-js
written in pure typescript, bundled for UMD, ESM and CJS
- 🛠️ Node.js CommonJS:
const PCA = require('pca-js') - 🛠️ Node.js ESM:
import PCA from 'pca-js'
Always get the updated CDN links at JSDELIVR. The below are just provided as an example.
- 🌍 Browser (Global):
<script src="https://cdn.jsdelivr.net/npm/pca-js@2.0.6/dist/pca.min.js"></script>→window.PCA - 🌍 Browser (ESM):
import PCA from 'https://cdn.jsdelivr.net/npm/pca-js@2.0.6/+esm'
Can use unpkg etc but only jsdelivr is actively supported and tested by me. Open an issue for better CDN recommends.
All methods are exposed through PCA global variable
Say you have data for marks of a class 4 students in 3 examinations on the same subject:
Student 1: 40,50,60
Student 2: 50,70,60
Student 3: 80,70,90
Student 4: 50,60,80
You want to examine whether it is possible to come up with a single descriptive set of scores which explains performance across the class. Alternatively, whether it would make sense to replace 3 exams with just one (and reduce stress on students).
First get the set of eigenvectors and eigenvalues (principal components and adjusted loadings)
var data = [[40,50,60],[50,70,60],[80,70,90],[50,60,80]];
var vectors = PCA.getEigenVectors(data);
//Outputs
// [{
// "eigenvalue": 520.0992658908312,
// "vector": [0.744899700771276, 0.2849796479974595, 0.6032503924724023]
// }, {
// "eigenvalue": 78.10455398035167,
// "vector": [0.2313199078283626, 0.7377809866160473, -0.6341689964277106]
// }, {
// "eigenvalue": 18.462846795484058,
// "vector": [0.6257919271076777, -0.6119361208615616, -0.4836513702572988]
// }]Now you'd need to find a set of eigenvectors that would explain a decent amount of variance across your exams (thus telling you if 1 test or 2 tests would suffice instead of three)
var first = PCA.computePercentageExplained(vectors,vectors[0])
// 0.8434042149581044
var topTwo = PCA.computePercentageExplained(vectors,vectors[0],vectors[1])
// 0.9700602484397556So if you wanted to have 97% certainty, that someone wouldn't just flunk out accidentally, you'd take 2 exams. But let's say you just wanted to take 1, explaining 84% of variance is good enough. And instead of taking the examination again, you just wanted a normalized score
var adData = PCA.computeAdjustedData(data,vectors[0])
// {
// "adjustedData": [
// [-22.27637101744241, -9.127781049780463, 31.316721747529886, 0.08743031969298887]
// ],
// "formattedAdjustedData": [
// [-22.28, -9.13, 31.32, 0.09]
// ],
// "avgData": [
// [-55, -62.5, -72.5],
// [-55, -62.5, -72.5],
// [-55, -62.5, -72.5],
// [-55, -62.5, -72.5]
// ],
// "selectedVectors": [
// [0.744899700771276, 0.2849796479974595, 0.6032503924724023]
// ]
// }The adjustedData is centered (mean = 0), but you could always set the mean to something like 50, to get scores of [-22.27637101744241, -9.127781049780463, 31.316721747529886, 0.08743031969298887].map(score=>Math.round(score+50)) equal to [28, 41, 81, 50] , and that's how well your students would have done, in the order of students.
var compressed = adData.formattedAdjustedData;
//[
// [-22.28, -9.13, 31.32, 0.09]
// ]
var uncompressed = PCA.computeOriginalData(compressed,adData.selectedVectors,adData.avgData);
//uncompressed.formattedOriginalData (lossy since 2 eigenvectors are removed)
// [
// [38.4, 56.15, 59.06],
// [48.2, 59.9, 66.99],
// [78.33, 71.43, 91.39],
// [55.07, 62.53, 72.55]
// ]Compare this to the original data to understand just how lossy the compression was
//Original Data
[
[40, 50, 60],
[50, 70, 60],
[80, 70, 90],
[50, 60, 80]
]
//Uncompressed Data
[
[38.4, 56.15, 59.06],
[48.2, 59.9, 66.99],
[78.33, 71.43, 91.39],
[55.07, 62.53, 72.55]
]
Find centered matrix from original data
Find deviation from mean for values in matrix
Singular Value Decomposition of matrix
Find the cumulative percentage explained variance by selected vectors (select vectors accordingly to view specific explained variance)
Get original data from the adjusted data after selecting a few eigenvectors
Get variance covariance matrix from the data, adjust n by one if the data is from a sample
Get adjusted data using principal components as selected
Get the principal components of data using the steps outlined above.
Same as computeAdjustedData(initialData,vectors[0]). Selecting only the top eigenvector which explains the most variance.
This license will remain consistent going forward with subsequent versions.
The license is GPL which is a better license imho for copyleft and packages that might derive this package.
Was MIT earlier.
LICENSE: GPL 3.0